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Year 11 Science · Describing motion with equations

Name: ______________________

Date: ____________

  1. 1. Which is a vector quantity?

    • ☐ (a) Speed
    • ☐ (b) Distance
    • ☐ (c) Mass
    • ☐ (d) Velocity
  2. 2. What does the gradient of a velocity–time graph represent?

    • ☐ (a) Displacement
    • ☐ (b) Acceleration
    • ☐ (c) Speed
    • ☐ (d) Time
  3. 3. Which equation would you use to find v when you know u, a and s but not t?

    • ☐ (a) v² = u² + 2as
    • ☐ (b) v = u + at
    • ☐ (c) s = ut + ½at²
    • ☐ (d) F = ma
  4. 4. A ball is dropped from rest. Ignoring air resistance, what is its speed after 2.0 s? (g = 9.8 m/s²)

    • ☐ (a) 9.8 m/s
    • ☐ (b) 4.9 m/s
    • ☐ (c) 19.6 m/s
    • ☐ (d) 39.2 m/s
  5. 5. A car accelerates uniformly from 10 m/s to 30 m/s in 5 s. What is its acceleration?

    • ☐ (a) 2 m/s²
    • ☐ (b) 4 m/s²
    • ☐ (c) 6 m/s²
    • ☐ (d) 8 m/s²
  6. 6. A ball is dropped from rest and falls for 2.0 s. How far does it fall in metres? (g = 9.8 m/s², ignore air resistance)

  7. 7. A car at 30 m/s brakes at a constant 6 m/s². How many seconds does it take to stop? (number)

  8. 8. On a velocity–time graph, a train moves at a constant 15 m/s for 20 s. What displacement in metres does the area represent? (number)

Answer sheet

  1. 1. Velocity — Velocity has both magnitude and direction.
  2. 2. Acceleration — Gradient = change in velocity ÷ time = acceleration.
  3. 3. v² = u² + 2as — v² = u² + 2as does not include t.
  4. 4. 19.6 m/s — v = u + at = 0 + 9.8 × 2.0 = 19.6 m/s.
  5. 5. 4 m/s² — a = (30 − 10) ÷ 5 = 4 m/s².
  6. 6. 19.6 — s = ½ × 9.8 × 2.0² = 4.9 × 4 = 19.6 m.
  7. 7. 5 — v = u + at: 0 = 30 − 6t, so t = 5 s.
  8. 8. 300 — Area of rectangle = 15 × 20 = 300 m.

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